Respuesta :
Answer:
[tex]\frac{x }{x^{2}-9 } +\frac{9}{x}=\frac{x^{2} }{x(x^{2}-9) }+\frac{9(x^{2}-9) }{x(x^{2} -9)}\\\\=\frac{10x^{2} -81}{x(x-3)(x+3)}[/tex]
Step-by-step explanation:
x / (x^2-9) + 9/x
x^2 / x(x^2-9) + 9(x^2-9) / x(x^2-9)
x^2 + 9(x^2-9) / x(x^2-9)
x^2 + 9x^2 -81
10x^2 -81 / x^3 -9x is the answer
x^2 / x(x^2-9) + 9(x^2-9) / x(x^2-9)
x^2 + 9(x^2-9) / x(x^2-9)
x^2 + 9x^2 -81
10x^2 -81 / x^3 -9x is the answer