Answer:
[tex]M_2=0.613M_1[/tex]
Explanation:
[tex]M_1[/tex] = Concentration of stock solution
[tex]M_2[/tex] = Concentration of solution
[tex]V_1[/tex] = Volume of stock solution = 19 mL
[tex]V_2[/tex] = Volume of solution = 0.31 L= 310 mL
We have the relation
[tex]M_1V_1=M_2V_2\\\Rightarrow M_2=\dfrac{M_1V_1}{V_2}\\\Rightarrow M_2=\dfrac{M_119}{310}\\\Rightarrow M_2=M_1\times\dfrac{19}{310}\\\Rightarrow M_2=0.613M_1[/tex]
[tex]\boldsymbol{\therefore M_2=0.613M_1}[/tex]
The concentration of the diluted solution will be 0.613 times the concentration of the stock solution.
