What are the respective concentrations (M) of Mg2+and Cl-afforded by dissolving 0.325 mol MgCl2 in water and diluting to 250 mL?A) 0.0013 and 0.0013B) 0.0013 and 0.0026C) 1.30 and.1.30D) 1.30 and 2.60E) 2.60 and 2.60

Respuesta :

Answer: D) 1.30 and 2.60

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in ml

molarity  of [tex]MgCl_2[/tex] = [tex]\frac{0.325\times 1000}{250ml}=1.30 M[/tex]

[tex]MgCl_2\rightarrow Mg^{2+}+Cl^{-}[/tex]

As 1 mole of [tex]MgCl_2[/tex] dissociates to give one mole of [tex]Mg^{2+}[/tex] and two moles of  [tex]Cl^-[/tex] ions .

Molarity of [tex]Mg^{2+}[/tex] = 1.30 M

Molarity of [tex]Cl^{-}[/tex] = [tex]1.3 M\times 2=2.60M[/tex]