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Two interfering sound waves have frequencies of 223 Hz and 214 Hz. Determine the beat period (in s) of the composite wave. (Hint: first determine the beat frequency.)

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Answer:

The beat period of the composite wave is 0.11 s.

Explanation:

Given;

frequency of the first sound wave, F₁ = 223 Hz

frequency of the second sound wave, F₂ = 214 Hz

The beat frequency is given as;

Fb  = F₁ - F₂

Fb = 223 Hz - 214 Hz

Fb = 9 Hz

The beat period is given as;

[tex]T_b = \frac{1}{F_b} \\\\T_b = \frac{1}{9} \\\\T_b = 0.11 \ s[/tex]

Therefore, the beat period of the composite wave is 0.11 s.

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