A ball is thrown from an initial height of 4 feet with an initial upward velocity of 30ft/s. The balls height h (in feet) after t seconds is given by the following. H=4+30t-16t^2n

Respuesta :

The maximum height of the ball is at 18.0625 feet which occurs at 0.9375 s

What is an equation?

An equation is an expression that shows the relationship between two or more variables and numbers.

Let h represent the height of the ball after t seconds, hence:

h(t) = 4 + 30t - 16t²

The maximum height is at h'(t) = 0, hence:

h'(t) = 30 - 32t

-32t + 30 = 0

t = 0.9375 s

h(0.9375) = 4 + 30(0.9375) - 16(0.9375)² = 18.0625 feet

The maximum height of the ball is at 18.0625 feet which occurs at 0.9375 s

Find out more on equation at: https://brainly.com/question/13763238

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