Respuesta :
Answer:
The net force acting on the mass is 16.523 N
Explanation:
The given mass of the object, m = 1.3 kg
The length of the inclined plane over which the mass slides = 8.7 × 10⁻¹ m
The time it takes the mass to slide = 0.37 s
Therefore, we apply the following kinematic equation of motion;
s = u·t + 1/2·a·t²
Where;
u = The initial velocity of the mass = 0 m/s
t = The time taken for the motion = 0.37 s
a = The acceleration
s = The distance moved in the motion = 8.7 × 10⁻¹ m = 0.87 m
Plugging in the values gives;
0.87 = 0 × t + 1/2 × a × 0.37²
∴ 0.87 = 1/2 × a × 0.37²
a = 0.87/(1/2 × 0.37²) ≈ 12.71 m/s²
The net force acting on the mass is F = Mass, m × Acceleration, a force = m × a
Therefore, the net force acting on the mass is F = 1.3 × 12.71 = 16.523
The net force acting on the mass, F = 16.523 N.
The net force acting on the mass along the incline is 16.523 N
From the information given:
- the mass of the object = 1.3 kg
- the length which corresponds to the distance (S) of the inclined plane = 8.7 × 10⁻¹ m
- the time taken = 0.37 s
According to the second equation of motion;
[tex]\mathbf{S = ut + \dfrac{1}{2}at^2}[/tex]
the initial velocity u = 0 m/s since the mass starts from the rest
∴
[tex]\mathbf{S =0(t) + \dfrac{1}{2}at^2}[/tex]
[tex]\mathbf{S = \dfrac{1}{2}at^2}[/tex]
2S = at²
[tex]\mathbf{a = \dfrac{2S}{t^2}}[/tex]
[tex]\mathbf{a = \dfrac{2\times 0.87 \ m}{0.37^2}}[/tex]
acceleration (a) = 12.71 m/s²
The net force now acting on the mass along the incline can now be estimated as:
[tex]\mathbf{F_{net} = ma}[/tex]
[tex]\mathbf{F_{net} = 1.3 \ kg \times 12.71 \ m/s^2}[/tex]
[tex]\mathbf{F_{net} = 16.523 \ N}[/tex]
Therefore, we can conclude that the net force acting on the mass along the incline is 16.523 N
Learn more about inclined planes here:
https://brainly.com/question/14983337?referrer=searchResults
