Answer:
[tex]\boxed {\boxed {\sf 299.568 \ Joules }}[/tex]
Explanation:
Kinetic energy can be found using the following formula:
[tex]E_k=\frac{1}{2}mv^2[/tex]
where m is the mass and v is the velocity.
The mass of the person is 60 kilograms and the velocity is 3.16 meters per second
[tex]m= 60 \ kg \\v= 3.16 \ m/s[/tex]
Substitute the values into the formula.
[tex]E_k=\frac{1}{2} (60 \ kg) *(3.16 \ m/s)^2[/tex]
First, evaluate the exponent.
- (3.16 m/s)²= (3.16 m/s) * (3.16 m/s) = 9.9856 m²/s²
[tex]E_k=\frac{1}{2}(60 \ kg ) (9.9856 \ m^2/s^2)[/tex]
Multiply 60 kg by 9.9856 m²/s²
[tex]E_k=\frac{1}{2} (599.136 \ kg*m^2/s^2)[/tex]
Multiply 599.136 kg*m²/s² by 1/2, or divide by 2.
[tex]E_k=299.568 \ kg*m^2/s^2[/tex]
- 1 kg*m²/s² is equal to 1 Joule
- Therefore, our answer of 299.568 kg*m²/s² is equal to 299.568 Joules.
[tex]E_k= 299.568 \ J[/tex]
The running person has a kinetic energy of 299.568 Joules.
