Answer:
Line 1 and Line 2: Perpendicular
Line 1 and Line 3: Neither
Line 2 and Line 3: Neither
Step-by-step explanation:
We will write all lines in slope intercept form i.e [tex]y=mx+b[/tex]
where m is slope.
And check
a) If two lines are parallel they have same slope [tex]m_1=m_2[/tex]
b) If two lines are perpendicular they have opposite reciprocal slopes i.e [tex]m_1=-\frac{1}{m_2}[/tex]
Equation for Line 1: [tex]y=-\frac{4}{3}x-4[/tex]
Already in slope-intercept form
Slope for Line 1 m is: [tex]\mathbf{m_1=-\frac{4}{3}}[/tex]
Equation for Line 2: [tex]6x-8y=-6[/tex]
Converting into slope-intercept form:
[tex]6x-8y=-6\\-8y=-6x-6\\y=\frac{-6x-6}{-8}\\y=\frac{-6x}{-8}+\frac{-6}{-8} \\y=\frac{3x}{4}+\frac{3}{4}[/tex]
Slope for Line 2 m is: [tex]\mathbf{m_2=\frac{3}{4}}[/tex]
Equation for Line 3: [tex]-4y=3x+7[/tex]
Converting into slope-intercept form:
[tex]-4y=3x+7\\y=-\frac{3}{4} -\frac{7}{4}[/tex]
Slope for Line 3 m is: [tex]\mathbf{m_3=-\frac{3}{4}}[/tex]
Now, finding answers
Line 1 and Line 2
Checking their slopes: [tex]\mathbf{m_1=-\frac{4}{3}}[/tex], [tex]\mathbf{m_2=\frac{3}{4}}[/tex]
Both lines are perpendicular because they have opposite reciprocal slopes
Line 1 and Line 3
Checking their slopes: [tex]\mathbf{m_1=-\frac{4}{3}}[/tex], [tex]\mathbf{m_3=-\frac{3}{4}}[/tex]
Slopes are neither same, nor opposite reciprocal, so they are neither
Line 2 and Line 3
Checking their slopes: [tex]\mathbf{m_2=\frac{3}{4}}[/tex], [tex]\mathbf{m_3=-\frac{3}{4}}[/tex]
Slopes are neither same, nor opposite reciprocal, so they are neither
The answers are:
Line 1 and Line 2: Perpendicular
Line 1 and Line 3: Neither
Line 2 and Line 3: Neither
