nickvictor49
contestada

An object is at rest when it undergoes a constant acceleration of 13 m/s2
for 5.0 seconds.
How far will it have traveled during this time?

Respuesta :

leena

Hi there!

[tex]\large\boxed{d = 162.5m}[/tex]

Find the distance traveled using the kinematic equation:

d = vi(t) + 1/2(a)(t²)

In this instance, vi = 0 because the object was initially at rest. Plug in the other values to solve:

d = 0t + 1/2(13)(5²)

d = 1/2(13)(25)

d = 162.5m

Otras preguntas