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During final exam weeks, many college students exercise to fuel their study sessions. Data from a recent survey are shown in the Venn diagram. Let M be the event that the student exercises in the morning and let A be the event that the student exercises in the afternoon.
What is the probability that a randomly chosen college student does not exercise in the morning?
A) 0.14
B) 0.24
C) 0.38
D) 0.75

During final exam weeks many college students exercise to fuel their study sessions Data from a recent survey are shown in the Venn diagram Let M be the event t class=

Respuesta :

Answer: D) 0.14

Explanation: Students in circle A and students in the center of the Venn diagram exercise in the morning

The probability that a randomly chosen college student does not exercise in the morning is;

C: 0.38

From the given venn diagram, we see that;

  • Probability that the student exercises in the afternoon; P(A) = 0.14 + 0.37 = 0.51

  • Probability that the student exercises in the morning; P(M) = 0.25 + 0.37 = 0.61

  • Probability that the students exercises in the morning and in the afternoon; P(A ∩ M) = 0.37

  • Probability that the student does not exercise in the morning nor afternoon; P(A ∪ M)' = 0.24

Now, we want to find the probability that the student does not exercise in the morning.

This is;

P(A ∩ M') + P(A ∪ M)' = 0.24 + 0.14

P(A ∩ M') + P(A ∪ M)' = 0.38

Read more about venn diagrams at; https://brainly.com/question/2099071