Answer: Explanation:
We have:
sin
2
(
x
)
+
sin
(
x
)
=
0
;
[
0
,
2
π
)
⇒
sin
(
x
)
(
sin
(
x
)
+
1
)
=
0
⇒
sin
(
x
)
=
0
⇒
x
=
0
,
(
π
−
0
)
,
(
π
+
0
)
,
(
2
π
−
0
)
or
⇒
sin
(
x
)
+
1
=
0
⇒
sin
(
x
)
=
−
1
⇒
x
=
π
+
π
2
⇒
x
=
0
,
3
π
2
,
π
Step-by-step explanation: