take father's age as x
if it is doubled i.e 2x .we get the answer as 20 less than 100 which means 100-20=80
accordingly the equation will be 2x=80
x=40
given that ,
son is 1/4 th of his father
hence ,
son = 1/4×(x)
I.e, 1/4×40 =10
Hope it helps
Using a system of equations, it is found that Alex's present age is of 10 years.
For the system, we consider that:
He is one-fourth the age of a his father, hence:
[tex]x = \frac{y}{4}[/tex]
If the age of the father is doubled, it is 20 years less than 100 years, hence:
[tex]2y = 100 - 20[/tex]
[tex]2y = 80[/tex]
[tex]y = \frac{80}{2}[/tex]
[tex]y = 40[/tex]
Then:
[tex]x = \frac{y}{4} = \frac{40}{4} = 10[/tex]
Alex's present age is of 10 years.
For a similar problem involving a system of equations, you can take a look at https://brainly.com/question/14183076
