Answer:
No. of Molecules = 18.06 x 10²³ molecules
No. of Atoms of P = 3 atoms
No. of Atoms of Na = 9 atoms
Total No. of Atoms = 24 atoms
Explanation:
FOR NUMBER OF MOLECULES:
[tex]No.\ of\ Molecules = (No.\ of\ Moles)(Avigadro's\ Number)\\No.\ of\ Molecules = (3)(6.02\ x\ 10^{23}\ molecules})\\[/tex]
No. of Molecules = 18.06 x 10²³ molecules
FOR NUMBER OF P ATOMS:
[tex]No.\ of\ Atoms\ of\ P = (No.\ of\ Moles)(N.\ of atoms of P)\\No.\ of\ Atoms\ of\ P = (3)(1\ atom})[/tex]
No. of Atoms of P = 3 atoms
FOR NUMBER OF Na ATOMS:
[tex]No.\ of\ Atoms\ of\ Na = (No.\ of\ Moles)(N.\ of atoms of Na)\\No.\ of\ Atoms\ of\ Na = (3)(3\ atom})[/tex]
No. of Atoms of Na = 9 atoms
FOR TOTAL NUMBER OF ATOMS:
[tex]Total\ No.\ of\ Atoms = (No.\ of\ Moles)(N.\ of\ atoms\ of\ Na + No.\ of\ atoms\ of\ P + No.\ of\ atoms\ of\ O)\\ Total\ No.\ of\ Atoms\ = (3)(3\ atoms + 1\ atom + 4\ atoms}) = (3)(8\ atoms)[/tex]
Total No. of Atoms = 24 atoms
