This question is based on the concept of addition. Therefore, the number of times were the boys able to make the jump on the ramp altogether without falling is 36.
Given:
Jared did it 8 times. Sam made the jump 4 more times than Jared, and Charlie only made the jump twice.
We need to determined the number of times were the boys able to make the jump on the ramp altogether without falling.
According to the question,
No. of times Jared jumps = 8 times
No. of times Sam jumps = 4 more times than Jared = 4 + 8 = 12
No. of times Charlie jumps = twice of Jared = 8 * 2 = 16
Therefore, the calculating the number of times jumps together. We would be added all the jumps.
We get,
⇒ 8 + 12 + 16 = 36
Therefore, the number of times were the boys able to make the jump on the ramp altogether without falling is 36.
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https://brainly.com/question/19829044
