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What is the equation of the line that passes through the points (–2, 2) and (0, 5)?

A. y = 3/2x + 5
B. y = –3/2x + 5
C. y = x – 5
D. y = x + 5

Respuesta :

apologiabiology
slope=(y2-y1)/(x2-x1) for points (x1,y1) and (x2,y2)
given (-2,2) and (0,5)
slope=(5-2)/(0-(-2))=3/(0+2)=3/2

y=mx+b
m=slope
y=3/2x+b
A is the answer

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