Answer:
The volume of cone B is twice the volume of cone A.
Step-by-step explanation:
Cone A
Height of cone = 3 m
Radius of Cone = 2 m
Volume of cone = [tex]\frac{1}{3} \pi r^{2} h[/tex]
= [tex]\frac{1}{3} \times 3.14 \times 2^{2} (3)[/tex]
= [tex]12.56 m^3[/tex]
Cone B
Height of cone = 6 m
Radius of Cone = 2 m
Volume of cone = [tex]\frac{1}{3} \pi r^{2} h[/tex]
= [tex]\frac{1}{3} \times 3.14 \times 2^{2} (6)[/tex]
= [tex]25.12 m^3[/tex]
Now [tex]12.56 \times 2 = 25.12 [/tex]
Thus the volume of cone B is twice the volume of cone A.
