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Hamburgers cost $2.50 and cheeseburgers cost $3.50 at a snack bar. Ben has sold no more than $30 worth of hamburgers and cheeseburgers in the first hour of business. Let x represent the number of hamburgers and y represent the number of cheeseburgers. The inequality 2.50x + 3.50y ≤ 30 represents the food sales in the first hour.

If Ben has sold 4 cheeseburgers, what is the maximum value of hamburgers Ben could have sold?

Respuesta :

scme1702
Using the inequality
2.50x + 3.50y ≤ 30
substituting y with the number of cheeseburgers sold
2.5x + 3.5(4) ≤ 30
 x = 6.4
The maximum number of hamburgers he can sell is 6
calculista

Answer:

The maximum value of hamburgers is [tex]6[/tex]

Step-by-step explanation:

Let

x-------> the number of hamburgers

y-----> the number of cheeseburgers

we know that

[tex]2.50x+3.50y\leq 30[/tex] -------> inequality that represent the situation

For [tex]y=4[/tex]

substitute in the inequality and solve for x

[tex]2.50x+3.50(4)\leq 30[/tex]

[tex]2.50x+14\leq 30[/tex]

[tex]2.50x\leq 30-14[/tex]

[tex]2.50x\leq 16[/tex]

[tex]x\leq 6.4[/tex]

so

The maximum value of hamburgers is [tex]6[/tex]

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