Standar molar entropies from a table:
CH3OH (l): 126.8 J / K*mol
O2 (g): 205.1 J/ K*mol
CO2(g): 213.7 J/K*mol
H2O(g): 188.8 J/J*mol
Now use the coefficients of the reaction and sum the product entropies less the reactant entropies:
4*188.8 + 2*213.7 - 3*205.1 - 2* 126.8 = 313.7 J/mol*K
Answer: option C) +3173.766 J/mol*K