The answer is B. p – 8; p ≠ –4
The expression is: [tex] \frac{ p^{2}-4p-32}{p+4} [/tex]
Since the the divisor cannot be zero, that means that p+4 cannot be zero:
p + 4 ≠ 0
⇒ p ≠ -4
Let's simplify this expression:
[tex]\frac{ p^{2}-4p-32}{p+4} = \frac{ (p+4)(p-8)}{p+4}[/tex]
Now, cancel out (p+4) and you will get:
[tex]\frac{ (p+4)(p-8)}{p+4} = p-8[/tex]
