Respuesta :
x - horizontal distance from peak to peak
y – difference between the altitudes of two peaks
Equations:
y/x = tan(17°)
(1100 – y)/x = tan(46°)
Solution:
y = (1100 tan(17°)) / (tan(17°) + tan(46°)) = 250.74 ft
x = y / tan(17°) = 820.12 ft
Horizontal distance from peak to peak is 820 ft.
Altitude of the taller peak is 5300 + 250 = 5550 ft.
The direct distance from peak to peak is √(x²+y²) = 857.6 ft.
y – difference between the altitudes of two peaks
Equations:
y/x = tan(17°)
(1100 – y)/x = tan(46°)
Solution:
y = (1100 tan(17°)) / (tan(17°) + tan(46°)) = 250.74 ft
x = y / tan(17°) = 820.12 ft
Horizontal distance from peak to peak is 820 ft.
Altitude of the taller peak is 5300 + 250 = 5550 ft.
The direct distance from peak to peak is √(x²+y²) = 857.6 ft.
Answer:
the altitude of the taller peak is equal to 5468.4 ft
Step-by-step explanation:
given,
altitude of the helicopter = 1000 ft
height of the mountain = 5210 ft
Angle of depression from helicopter = 43°
Angle of depression from mountain = 18°
[tex]tan 18 = \dfrac{h}{s}[/tex]
[tex]tan 43 = \dfrac{1000-h}{s}[/tex]
[tex]\dfrac{h}{tan 18} = \dfrac{1000-h}{tan 43 }[/tex]
2.87 h = 1000 - h
3.87 h = 1000
h = 258.4 ft
Taller peak =
= 5210+258.4
= 5468.4 ft
the altitude of the taller peak is equal to 5468.4 ft
