Respuesta :
(5x^2-25x)/x
simplify
((x)(5)(x-5))/x=5(x-5)=5x-25=f(x)
(just fyi, that x we cancled is a hole)
set to zero
5x-25=0
5x=25
divide 5
x=5
zeroe is at x=5
or (5,0)
x=5 is answer
simplify
((x)(5)(x-5))/x=5(x-5)=5x-25=f(x)
(just fyi, that x we cancled is a hole)
set to zero
5x-25=0
5x=25
divide 5
x=5
zeroe is at x=5
or (5,0)
x=5 is answer
Answer:
x=5
Step-by-step explanation:
[tex]f(x)= \frac{5x^2-25x}{x}[/tex]
To find out zeros we replace f(x) with 0
[tex]0= \frac{5x^2-25x}{x}[/tex]
Now solve for x
first we divide the numerator by x
[tex]0=5x-25[/tex]
Now we facor out GCF 5
[tex]0=5(x-5)[/tex]
Divide by 5 on both sides
[tex]0=x-5[/tex]
Add 5 on both sides
x= 5
zero of the function is x=5