Respuesta :

HomertheGenius
Vector u :
u = 6 i - 3 j
The magnitude of vector u :
| u | = [tex] \sqrt{6 ^{2}+(-3) ^{2} } = \sqrt{36+9}= \\ \sqrt{45}= \sqrt{9*5}=3 \sqrt{5} [/tex]
Answer:
The magnitude of vector u is 3√5. 

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