The area of a square is found by squaring one of its sides, (A = s2). A certain square has an area of z2 + 18z + 81. Factor the trinomial to find a side of the square.
a. side = z + 27
b. side = z + 18
c. side = z + 9

Respuesta :

A = s²
A =  z² + 18 z + 81
z² + 18 z + 81 = z² + 9 z + 9 z + 81 = z ( z + 9 ) + 9 ( z + 9 ) =
= ( z + 9 ) ( z + 9 ) = ( z + 9 )²
Answer:
C ) side = z + 9 

Answer:

option c is correct.

side = z+9

Step-by-step explanation:

Area of a square(A) is given by:

[tex]A = s^2[/tex]

where,

s is the side of the square.

As per the statement:

A certain square has an area of  [tex]z^2 + 18z + 81.[/tex]

⇒[tex]A = z^2 + 18z + 81[/tex]

Substitute in [1] we have;

[tex]z^2 + 18z + 81 = s^2[/tex]

Taking square root both sides we have;

[tex]\sqrt{z^2 + 18z + 81} =s[/tex]

Using identity rule:

[tex](a+b)^2 =a^2+2ab+b^2[/tex]

then;

[tex]\sqrt{z^2 + 2(1)(9)z + 9^2} =s[/tex]

⇒[tex]\sqrt{(z+9)^2} =s[/tex]

Simplify:

[tex]z+9 = s[/tex]

or

s = z+9

Therefore,  a side of the square. is, z+9