λ[tex] = 550 * 10^{-9}\] m.
D = 3.50*10^-6 m.[/tex]
[tex]d = 10 m.
m = 1
2x = ?[/tex]
Then you need to find x when n=1
or
[tex]sinθ=λ/w=524x10^-9/0.0033=1.59x10^-4 [/tex]
≈θ for θ<<1 , so θ=[tex]1.59x10^-4 radians[/tex]
Then you can find rhe distance of bright fringe from the center:[tex]d= θD=1.59x10^-4x10m ≈ 1.6 mm[/tex]
