The value of x "[tex]\frac{5}{7}[/tex]" and the value of y is "4".
Linear equation:
Given equation are:
[tex]7x-2y=-3\\\\14x+y=14[/tex]
x,y=?
Let
[tex]7x-2y=-3..........................(a)\\\\14x+y=14.........................(b)\\[/tex]
solve equation (a)
[tex]\to 7x-2y=-3\\\\\to 7x=-3+2y\\\\\to x=\frac{-3+2y}{7}................(d)\\[/tex]
putting the value of x into equation (b):
[tex]\to 14(\frac{-3+2y}{7}) +y=14\\\\\to 2(-3+2y) +y=14\\\\\to -6+4y +y=14\\\\\to 5y=20\\\\\to y=\frac{20}{5}\\\\ \to y=4[/tex]
Putting the value of y into the equation (d):
[tex]\to x=\frac{-3 +2(4)}{7}\\\\\to x=\frac{-3 +8}{7}\\\\\to x=\frac{5}{7}\\\\[/tex]
Therefore the final value of x is "[tex]\frac{5}{7}[/tex]" and y is "4".
Find out more information about Linear equations here:
brainly.com/question/322601
