Answer:
Numbers in the solution set of this problem = ( -5, ∞)
Step-by-step explanation:
Let the number be x.
Two-fifths of one less than a number [tex]=\frac{2}{5}(x-1)[/tex]
Three-fifths of one more than a number [tex]=\frac{3}{5}(x+1)[/tex]
We have two-fifths of one less than a number is less than three-fifths of one more than that number
That is
[tex]\frac{2}{5}(x-1)<\frac{3}{5}(x+1)\\\\\frac{2}{5}x-\frac{2}{5}<\frac{3}{5}x+\frac{3}{5}\\\\\frac{x}{5}+1>0\\\\x>-5[/tex]
Numbers in the solution set of this problem = ( -5, ∞)
