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Answer:

 [tex]\sqrt{16x^{36} }[/tex] =   ± 4 * [tex]\{x^{18}}[/tex].

Step-by-step explanation:

Given : [tex]16x^{36}[/tex].

To find : What is the square root.

Solution : We have given that  [tex]16x^{36}[/tex].

Taking square root

[tex]\sqrt{16x^{36} }[/tex].

BY the radical rule :

[tex]\sqrt{a*b} = \sqrt{a} *\sqrt{b}[/tex].

So, we can write

[tex]\sqrt{16x^{36} }[/tex] = [tex]\sqrt{16} *\sqrt{x^{36}}[/tex].

We know that  [tex]\sqrt{16}[/tex]= 4  

  [tex]\sqrt{x^{36}}[/tex] =  [tex]\{x^{36/2}}[/tex].

Then [tex]\sqrt{16x^{36} }[/tex] =   ± 4 *  [tex]\{x^{18}[/tex].

Therefore,  [tex]\sqrt{16x^{36} }[/tex] =   ± 4 *  [tex]\{x^{18}[/tex].