Answer:
The correct answer is option C.
Explanation:
Atomic mass of iron = 55.845 g/mol
Atomic mass of oxygen = 15.999 g/mol
Mass of 1 mole of iron(III) oxide , [tex]Fe_2O_3[/tex]:
[tex]2\times 55.845 g/mol+3\times 15.999 g/mol=159.687 g/mol[/tex]
159.687 g/mol ≈ 159.70 g/mol
159.70 g/mol is the mass of one mole of iron(III) oxide.