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A table showing Number, Value, and Total Value. The first row shows Nickels, with the entries, n, 0.05, and 0.05 n. The second row shows Quarters, with the entries 36 minus n, 0.25, and 0.25 left-parenthesis 36 minus n right-parenthesis. The last row has Total, with the entries 36, blank, 6.
Alexandra has 36 coins valued at $6.00. She has only nickels and quarters. Which equation can be used to solve for the number of nickels, n?

0.05n + 0.25(36 – n) = 6
0.05n + 0.25(36 – n) = 36
n + 0.05 = 0.05n
n + (36 – n) = 36

Respuesta :

Answer:

a- 0.05n + 0.25(36 – n) = 6

Step-by-step explanation:

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The value of each coin (Nickels and Quarters) determines their number in a money sum

The correct option that gives the equation that can be used to solve for the number of nickels, n, is option;

0.05·n + 0.25·(36 - n) = 6

Reason:

The given equation can be presented as follows;

[tex]\begin{array}{|c|c|c|c|}&\mathbf{Number}&\mathbf{Value}&\mathbf{Total \ value}\\&&&\\Nickels&n&0.05&0.05 \cdot n\\Quarters&36 - n&0.25 & 0.25 \cdot(36 - n)\\&&&\\\mathbf{Total}&36&&6\end{array}\right][/tex]

From the above table, we have;

0.05·n + 0.25·(36 - n) = 6

Solving the above equation gives;

0.05·n + 9 - 0.25·n = 6

-0.2·n = 6 - 9 = -3

[tex]n = \dfrac{3}{0.2} = 15[/tex]

Therefore;

The equation that can be used to solve for the number of nickels, n, is; 0.05·n + 0.25·(36 - n) = 6

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