You roll a unbalanced die 500 times, and a 3-spot is obtained 110 times. The probability of obtaining the 3-spot for this die is approximately?

Respuesta :

Answer: [tex]\dfrac{11}{50}[/tex]

Step-by-step explanation:

Formula: Probability = [tex]\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}[/tex]

Given: Total number of times unbalanced die thrown = 500 (Total outcomes)

Number of times 3-spot is obtained = 110  (Favourable outcomes)

The probability of obtaining the 3-spot for this die [tex]=\dfrac{110}{500}[/tex]

[tex]=\dfrac{11}{50}=0.22[/tex]

The probability of obtaining the 3-spot for this die is 0.22 .