I think you wrote an incomplete question. With a little research, I was able to find a question similar to you which is attached below. So, I would solve your question based on the question attached below, which anyways would clear your concept.
Answer:
[tex]g(x)[/tex] is the graph of [tex]f(x)[/tex] translated left [tex]3[/tex] units. Also, the comparison graph is attached below.
Step-by-step explanation:
Considering the complete question attached below
Given the function
[tex]f\left(x\right)\:=\:4x+1[/tex]
As for [tex]g(x)=f(x-h)[/tex], the graph of [tex]g(x)[/tex] is the graph of [tex]f(x)[/tex] translated right h units when '[tex]h[/tex]' is greater than zero, and left | [tex]h[/tex] | units when h is lesser than zero.
so it is clear if
[tex]g(x)=4(x+3)+1[/tex] and [tex]f\left(x\right)\:=\:4x+1[/tex], then [tex]g(x) = f(x+3)[/tex].
Hence, [tex]h = -4[/tex] ( lesser than zero i.e. h < 0).
Therefore, [tex]g(x)[/tex] is the graph of [tex]f(x)[/tex] translated left [tex]3[/tex] units. Also, the comparison graph is attached below.
