Right triangle LMN is shown. What is the length of the hypotenuse, x, of triangle LMN? Round your answer to three decimal Places. Use the equation below.
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Answer:
55.866 ft
Step-by-step explanation:
[tex] c^2 = a^2 + b^2 [/tex]
[tex] x^2 = 40^2 + 39^2 [/tex]
[tex] x^2 = 1600 + 1521 [/tex]
[tex] x^2 = 3121 [/tex]
[tex] x = \sqrt(3121} [/tex]
[tex] x = 55.8659 [/tex\
Answer: 55.866 ft
The length of the hypotenuse, x, of triangle LMN to 3 decimal place is
55.866 ft
using Pythagoras theorem,
c² = a² + b²
where
c = hypotenuse
a and b are the 2 other legs.
Therefore,
40²+ 39² = x²
1600 + 1521 = x²
x² = 3121
square root both sides
x = √3121
x = 55.8659108939
x ≈ 55.866 ft
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