Answer:
General Form of Equation of a line that passes through the point (-8,6) and has a slope of 3/4 is:
[tex]\frac{3}{4}x-y+12=0[/tex]
Step-by-step explanation:
We need to find equation of line that passes through the point (-8,6) and has a slope of 3/4 in general form.
The general form of linear equation is [tex]Ax+By+C=0[/tex]
First we will use slope-intercept form i.e, [tex]y=mx+b[/tex] to find equation and then write it in general form.
Where m is slope and b is y-intercept.
We are given slope = 3/4 but y-intercept is not given and we need to find.
Finding y-intercept
Using the point (-8,6) and slope m = 3/4 we can find y-intercept
[tex]y=mx+b\\6=\frac{3}{4}(-8)+b\\6=3(-2)+b\\6=-6+b\\b=6+6\\b=12[/tex]
So, y-intercept b is 12
Equation of line
The line has slope m=3/4 and y-intercept b is 12, the equation is:
[tex]y=mx+b\\y=\frac{3}{4}x+12[/tex]
General Form of Equation of a line that passes through the point (-8,6) and has a slope of 3/4 is:
[tex]\frac{3}{4}x-y+12=0[/tex]
