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The diagram (picture) shows the speed-time graph of a body moving in a straight line.
(a) Calculate he acceleration of the body during the first 15 seconds.
(b) Calculate the distance moves by the body in the first 40 seconds of its motion.
(c) Given that the body decelerate at 1.25 m/s[tex]^{2}[/tex]

The diagram picture shows the speedtime graph of a body moving in a straight line a Calculate he acceleration of the body during the first 15 seconds b Calculat class=

Respuesta :

oscar236

Answer:

Below.

Step-by-step explanation:

(a)

The acceleration = the slope of the graph (change of velocity / time)

= 25/15

= 1.67 m/s/s.

(b)

The distance moved = the area under the graph for the first 0 seconds,

= area of the first triangle + area of the rectangle with height 25 and length (40 - 15)

= 1/2 * 15 * 25  + (40-15) * 25

= 187.5 + 625

= 812.5 m.

(c). ? what is the question?

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