samiyakhan2
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7
The diagram shows a wooden beam PQ, of negligible weight, which is attached to a wall by a
hinge at P and kept in a horizontal position by a vertical rope attached at Q.
The beam is 3.0m in length.
A man of weight 800 N walks along the beam from P to Q.
wall
man
-rope
beam
Р
Q
hinge
1200
What is the distance of the man from P when the tension in the rope at Q becomes equal to
500N?
Gadifada

7 The diagram shows a wooden beam PQ of negligible weight which is attached to a wall by a hinge at P and kept in a horizontal position by a vertical rope attac class=

Respuesta :

Answer:

Explanation:

Taking moment of forces about the hinge ,

moment of weight of man = 800 x p where p is his distance of man from hinge , in clockwise direction .

moment of tension force in rope in anticlockwise direction

= 500 x 3

For rotational balancing

800 x p = 500 x 3

p = 1.875 m .

temdan2001

From the principle of moment, the distance of the man from P is 1.9 m

From the question, below are the given parameters;

  • The Length of the beam = 3m
  • The weight of the man = 800 N
  • The tension in the string = 500 N

As the man walks toward the string, the tension on it will act downward, while the normal reaction on the man will act upward.

From the principle of moment,

Clockwise moment = anticlockwise moment

Let us take our moment from point P. That is,

500 x 3 = 800 x d

Make d the subject of formula

d = 1500 / 800

d = 1.875 m  

Therefore, the distance of the man from P when the tension in the rope at Q becomes equal to 500N is 1.9 meters approximately.

Learn more about moment here: https://brainly.com/question/6278006

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