Respuesta :
Answer:
The correct option is;
D.) The molecular masses of the gases, because the gas molecules have the same average kinetic energy and mass can be calculated using the equation, [tex]KE_{avg} = \dfrac{1}{2} \times m \times v^2[/tex]
Explanation:
The graph shows the proportion of the atoms of each gas have a given velocity
The given parameters of the graphs are;
The dependent variable of the graph = The number of molecules
The independent variable = The molecular speed (m/s)
The temperature of the gases = The same temperature
[tex]v_{rms} = \sqrt{\dfrac{3 \cdot R \cdot T}{MW} }[/tex]
Therefore, from the above equation, at constant temperature, the root mean square velocity varies inversely as the molecular weight
Similarly from the kinetic energy equation, we have;
[tex]KE_{avg} = \dfrac{1}{2} \times m \times v^2[/tex]
Whereby, the energy contained in each of the four gas are the same, we have;
For increasing molecular mass by a factor of 2, the velocity decreases by a factor of 4.
The property that can be ranked is ; ( D ) The molecular masses of the gases, because the gas molecules have the same average kinetic energy and mass can be calculated using the equation [tex]K.E_{avg} = 1/2 mv^2[/tex]
From the attached graph the proportion of atoms are matched with a given velocity.
- The number of molecules is the dependent variable
- The molecular speed ( m/s ) is an independent variable while
- Temperature of the gases is a constant variable.
The energy contained in each of the gases is the same therefore the average kinetic energy of the molecules is the same, also the root mean square of velocity varies inversely as the molecular weight when temperature is kept constant for molecules of the gases.
Hence we can conclude that the property that can be correctly ranked using the information from the graph is The molecular masses of the gases, because the gas molecules have the same average kinetic energy and mass can be calculated using the equation [tex]K.E_{avg} = 1/2 mv^2[/tex]
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