Calculate the total heat flow, qtotal, when 15.0 g of water is cooled from 115°C to -20.0°C. The heat of fusion of water is 335 J/g, and the heat of vaporization of water is 2.26 kJ/g. The specific heat of liquid water is 4.183 J/gºC, the specific heat of steam is 2.0 J/g°C, and the specific heat of ice is 2.1 J/g°C.

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nikitarahangdaleVT nikitarahangdaleVT · Answer 2 · 2022-04-23T12:28:09+02:00

The total heat flow of water from the state of ice to vapor form is equal to 38,925 J.

How do we calculate total heat?

Total heat flow from ice to vapor form of water will be calculated as:
Total heat = Heat of fusion + Heat of vaporization

Given that, mass of water = 15g

Heat of fusion of water = 15g × 335J/g = 5025 J

Heat of vaporization of water = 2.26kJ/g × 15g = 33.9 kJ = 33900 J

Total heat flow = 5025 + 33900 = 38925 J

Heance total flow of heat is 38,925 J.

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