Answer:
[tex]\boxed {\boxed {\sf a= -2 \ m/s^2}}[/tex]
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
[tex]a=\frac{v_f-v_i}{t}[/tex]
The final velocity of the cat was 0 meters per second and the initial velocity was 10 meters per second. The time was 5 seconds.
[tex]v_f=0 \ m/s\\v_i=10 \ m/s\\t= 5 \ s[/tex]
Substitute the values into the formula.
[tex]a=\frac{0 \ m/s-10 \ m/s}{5 \ s}[/tex]
Solve the numerator.
[tex]a=\frac{-10 \ m/s}{5 \ s}[/tex]
Divide.
[tex]a= -2 \ m/s^2[/tex]
The acceleration of the cat was -2 m/s². The negative acceleration indicates slowing down or stopping.
