Is the following relation a function? Yes or no
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Answer:
It is a many-to-many function but not a one-to-ine function hence, it cannot be represented a a function in an expression
Step-by-step explanation:
Topic: Functions
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Answer: No
Explanation: I think that the least confusing way to do
this problem is to first write down the ordered pairs that
are represented by this mapping diagram.
So we have {(6,3), (-1, 2), (-1, -1), (4, 3)}.
In order for a relation to be a function, each x-coordinate needs
to appear once unless we have a repeated ordered pair.
Since we have the same x-coordinate in two of
our ordered pairs, this relation cannot be a function.
In terms of the mapping diagram, you can see that we have
an x that is paired with two different y's.
So this does not fit the definition of a function which states
that each x must be paired with exactly one y.