Answer:
19, 21, 23
Step-by-step explanation:
Let the first odd number be n.
Then the second, consecutive odd number will be (n+2).
And the third will be (n+4).
We know that they sum to 63. Hence, we can write the following equation:
[tex]n+(n+2)+(n+4)=63[/tex]
Solve for n. Combine like terms:
[tex]3n+6=63[/tex]
Subtract 6 from both sides:
[tex]3n=57[/tex]
Divide both sides by 3:
[tex]n=19[/tex]
Hence, the first odd number is 19.
Therefore, our sequence is: 19, 21, 23.
Note: If we get an even or non-integer value for our n, then there are no three consecutive odd integers that exists that sum to 63.
19,21,23
The sum of three consecutive odd numbers is 63. Find the numbers.
Three consecutive odd numbers be:
sum of three consecutive odd numbers is 63
.°. x+(x+2)+(x+4)=63
→x+x+x=63-2-4
→3x=63-6
→3x=57
→x=57/3
→x=19
We get value of x → 19
Now put values in each number
First odd number= x
.°.First odd number=19
Second odd number =x+2
.°. Second odd number= 19+2
Second odd number = 21
Third odd number =x+4
.°.Third odd number=19+4
Third odd number=23
hope it helps!♡
