We are given:
Initial velocity (u) = 32 m/s
Acceleration (a) = 3 m/s²
Displacement (s) = 40 m
Final Velocity (v) = v m/s
Solving for the Final Velocity:
from the third equation of motion:
v² - u² = 2as
replacing the variables
v² - (32)² = 2(3)(40)
v² = 240 + 1024
v² = 1264
v = √1264
v = 35.5 m/s
Therefore, the velocity of the bike after travelling 40 m is 35.5 m/s
The bike's velocity after covering 40 m distance is 35.55 m/s.
Explanation:
Given:
The initial velocity of the bike = 32 m/s
The rate of acceleration of the bike = 3 ms^2
Distance covered by the bike = 40 m
To find:
The final velocity of the bike.
Solution:
The initial velocity of the bike = u = 32 m/s
The rate of acceleration of the bike = a = 3 ms^2
Distance covered by the bike = s = 40 m
The final velocity of the bike = v
Using the third equation of motion, which is written as :
[tex]v^2-u^2=2as\\v^2-(32m/s)^2=2\times 3m/s^2\times 40m\\v^2-1024 m^2/s^2=240 m^2/s^2\\v^2=240 m^2/s^2+1024 m^2/s^2\\v^2=1264 m^2/s^2\\v=35.55 m/s[/tex]
The bike's velocity after covering 40 m distance is 35.55 m/s.
Learn more about equations of motion here:
brainly.com/question/24486792?referrer=searchResults
brainly.com/question/20515145?referrer=searchResults
