Answer:
[tex]11.3\ \text{g/cm}^3[/tex]
[tex]7.92\ \text{g/cm}^3[/tex]
[tex]238.1\ \text{cm}^3[/tex]
Explanation:
8) Volume of lead
[tex]V=4.5\times 5.2\times 6\\\Rightarrow V=140.4\ \text{cm}^3[/tex]
m = Mass of block = 1587 g
Density is given by
[tex]\rho=\dfrac{m}{V}\\\Rightarrow \rho=\dfrac{1587}{140.4}\\\Rightarrow \rho=11.3\ \text{g/cm}^3[/tex]
Density of lead is [tex]11.3\ \text{g/cm}^3[/tex]
9) Volume of lead = Volume of water displaced = (49.1-45.5) = 3.6 mL = [tex]3.6\ \text{cm}^3[/tex]
m = Mass of iron = 28.5 g
Density is given by
[tex]\rho=\dfrac{m}{V}\\\Rightarrow \rho=\dfrac{28.5}{3.6}\\\Rightarrow \rho=7.92\ \text{g/cm}^3[/tex]
The density of iron is [tex]7.92\ \text{g/cm}^3[/tex]
10) m = Mass of silver = 2500 g
[tex]\rho[/tex] = Density of silver = [tex]10.5\ \text{g/cm}^3[/tex]
Volume is given by
[tex]V=\dfrac{m}{\rho}\\\Rightarrow V=\dfrac{2500}{10.5}\\\Rightarrow V=238.1\ \text{cm}^3[/tex]
The volume of silver is [tex]238.1\ \text{cm}^3[/tex]
