Let a, b, and c be constants, and let x be a variable. Which of the following is
equivalent to a(x + b) < c when a < 0? (Rearranging Formulas) IMAGE BELOW :D

Let a b and c be constants and let x be a variable Which of the following is equivalent to ax b lt c when a lt 0 Rearranging Formulas IMAGE BELOW D class=

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Answer:

C

Step-by-step explanation:

We are given that:

[tex]a(x+b)<c[/tex]

Where a < 0.

To solve for x, we can divide both sides by a.

Since a < 0, a is negative. Hence, we must flip the inequality sign. This yields:

[tex]\displaystyle x + b > \frac{c}{a}[/tex]

Subtract b from both sides. Hence:

[tex]\displaystyle x>\frac{c}{a}-b[/tex]

In conclusion, our answer is C.