Respuesta :
Answer: lithium < strontium < magnesium < tellurium < chlorine < oxygen
Explanation:
Ionization energy is the energy required to remove the most loosely bound electron from an isolated gaseous atom.
In a period, the ionization energy increases as we move across a period as the size decreases. The electrons get added to the same shell and the nuclear charge increases.The valence shell moves nearer to the nucleus. Thus more energy is required to remove the valence electron.
In a group , the ionization energy decreases from top to bottom as we move down a group. The size increases as the electrons get added up in the new shell, the electron in the outermost orbital gets far away from the nucleus. And hence, the electron will be easier to remove. Thus, lesser energy is required to remove the valence electron.
The correct order of increasing ionization energy will be:
lithium < strontium < magnesium < tellurium < chlorine < oxygen
Ionization energy is the energy required to remove the most loosely bound electron from the last shell.
In the periodic table, there are groups and periods.
- Group represents the vertical column.
- The period represents the horizontal rows.
In a period, the ionization energy increases as we move across a period as the size decreases. The electrons get added to the same shell and the nuclear charge increases.
The valence shell moves nearer to the nucleus. Thus more energy is required to remove the valence electron.
In a group, the ionization energy decreases from top to bottom as we move down a group.
The size increases as the electrons get added up in the new shell, the electron in the outermost orbital gets far away from the nucleus. And hence, the electron will be easier to remove. Thus, lesser energy is required to remove the valence electron.
The correct order of increasing ionization energy is:
lithium < strontium < magnesium < tellurium < chlorine < oxygen
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