Answer:
1.2 × 10²⁴ molecules NH₃
General Formulas and Concepts:
Chemistry
Explanation:
Step 1: Define
34 grams NH₃
Step 2: Define conversions
Avogadro's Number
Molar Mass of N - 14.01 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of NH₃ - 14.01 + 3(1.01) = 17.04 g/mol
Step 3: Convert
[tex]34 \ g \ NH_3(\frac{1 \ mol \ NH_3}{17.04 \ g \ NH_3} )(\frac{6.022 \cdot 10^{23} \ molecules \ NH_3}{1 \ mol \ NH_3} )[/tex] = 1.20157 × 10²⁴ molecules NH₃
Step 4: Check
We are given 2 sig figs. Follow sig fig rules.
1.20157 × 10²⁴ molecules NH₃ ≈ 1.2 × 10²⁴ molecules NH₃
