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As shown in the diagram below, a rope attached to a 500.-kilogram crate is used to exert a force of 45 newtons at an angle of 65 degrees above the horizontal 45 N at an angle of 65 degrees above the horizontal.
500 kg
The horizontal component of the force acting on the crate is?

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Answer:

19.01 N

Explanation:

F = Force being applied to the crate = 45 N

[tex]\theta[/tex] = Angle at which the force is being applied = [tex]65^{\circ}[/tex]

Horizontal component of force is given by

[tex]F_x=F\cos\theta\\\Rightarrow F_x=45\times \cos65^{\circ}\\\Rightarrow F_x=19.01\ \text{N}[/tex]

The horizontal component of the force acting on the crate is 19.01 N.

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