Answer:
4 pounds of wooden blocks and 6 pounds of plastic bricks should be used.
Step-by-step explanation:
Let w = wooden block
Let p = plastic bricks
Given the following data;
Price of wooden block per pounds = $5
Price of plastic brick per pounds = $10
*Translating the word problem into an algebraic equation*
For the 10-pound mixture;
[tex] w + p = 10[/tex] .........equation 1
For the $80 mixture;
[tex] 5w + 10p = 80[/tex] ..........equation 2
Solving the linear equation by using the substitution method;
Making w the subject in equation 1:
[tex] w = 10 - p[/tex] .......equation 3
Substituting "w" into equation 2;
[tex] 5(10 - p) + 10p = 80 [/tex]
Simplifying the equation, we have;
[tex] 50 - 5p + 10p = 80 [/tex]
[tex] 50 + 5p = 80 [/tex]
Rearranging the equation, we have;
[tex] 5p = 80 - 50[/tex]
[tex] 5p = 30 [/tex]
[tex] p = \frac {30}{5} [/tex]
p = 6 pounds (For the plastic brick).
To find w;
Substituting "p" into equation 3;
[tex] w = 10 - 6[/tex]
w = 4 pounds (For the wooden block).