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contestada

Given that n^2/3 = 8 and n> 0
work out the value of n.

Give your answer in the form a square root b where a and b are integers.

Respuesta :

Answer:

16[tex]\sqrt{2}[/tex]

Step-by-step explanation:

Using the rule of exponents/ radicals

[tex]a^{\frac{m}{n} }[/tex] = [tex]\sqrt[n]{a^{m} }[/tex] , then

[tex]n^{\frac{2}{3} }[/tex] = [tex]\sqrt[3]{n^2}[/tex] , then

[tex]\sqrt[3]{n^2}[/tex] = 8 ( cube both sides )

n² = 8³ ( take the square root of both sides )

n = [tex]\sqrt{8^3}[/tex]

   = [tex]\sqrt{512}[/tex]

   = [tex]\sqrt{256(2)}[/tex]

   = [tex]\sqrt{256}[/tex] × [tex]\sqrt{2}[/tex]

   = 16[tex]\sqrt{2}[/tex]