Answer:
The equation of the line, in slope-intercept form, that passes through (3,-1) and has a slope = -2/3 is:
[tex]\mathbf{y=-\frac{2}{3}x+1}[/tex]
Step-by-step explanation:
We need to write equation of the line, in slope-intercept form, that passes through (3,-1) and has a slope = -2/3.
The equation for slope-intercept form is: [tex]y=mx+b[/tex]
where m is slope and b is y-intercept.
We are given slope m = -2/3 and we need to find y-intercept i.e b to write equation of line.
Using point (3,-1) and slope m=-2/3 we can find y-intercept i.e b
[tex]y=mx+b\\-1=-\frac{2}{3}(3)+b\\-1=-2+b\\b=-1+2\\b=1[/tex]
So, y-intercept b = 1
The equation of the line, in slope-intercept form, that passes through (3,-1) and has a slope = -2/3 is:
[tex]y=mx+b\\\mathbf{y=-\frac{2}{3}x+1}[/tex]
