the time, t, in seconds, is required for an object accelerating at a constant rate of a meters/second to travel a distance of d meters is given this equation
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Answer:
C. [tex] d = \frac{at^2}{2} [/tex]
Step-by-step explanation:
Given:
[tex] t = \sqrt{\frac{2d}{a}} [/tex]
Required:
Make d the subject of the formula.
SOLUTION:
[tex] t = \sqrt{\frac{2d}{a}} [/tex]
Square both sides
[tex] t^2 = (\sqrt{\frac{2d}{a}})^2 [/tex]
[tex] t^2 = \frac{2d}{a} [/tex]
Multiply both sides by a
[tex] a*t^2 = \frac{2d}{a}*a [/tex]
[tex] at^2 = 2d [/tex]
Divide both sides by 2
[tex] \frac{at^2}{2} = \frac{2d}{2} [/tex]
[tex] \frac{at^2}{2} = d [/tex]
[tex] d = \frac{at^2}{2} [/tex]